4^2x-7=7^x+3

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Solution for 4^2x-7=7^x+3 equation: 



4^2x-7=7^x+3

We move all terms to the left:

4^2x-7-(7^x+3)=0

We get rid of parentheses

4^2x-7^x-3-7=0

We add all the numbers together, and all the variables

4^2x-7^x-10=0

We move all terms containing x to the left, all other terms to the right

4^2x-7^x=10

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